47-x[3x+4]=2[-17-2x]+81

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Solution for 47-x[3x+4]=2[-17-2x]+81 equation:


Simplifying
47 + -1x[3x + 4] = 2[-17 + -2x] + 81

Reorder the terms:
47 + -1x[4 + 3x] = 2[-17 + -2x] + 81
47 + [4 * -1x + 3x * -1x] = 2[-17 + -2x] + 81
47 + [-4x + -3x2] = 2[-17 + -2x] + 81
47 + -4x + -3x2 = [-17 * 2 + -2x * 2] + 81
47 + -4x + -3x2 = [-34 + -4x] + 81

Reorder the terms:
47 + -4x + -3x2 = -34 + 81 + -4x

Combine like terms: -34 + 81 = 47
47 + -4x + -3x2 = 47 + -4x

Add '-47' to each side of the equation.
47 + -4x + -47 + -3x2 = 47 + -47 + -4x

Reorder the terms:
47 + -47 + -4x + -3x2 = 47 + -47 + -4x

Combine like terms: 47 + -47 = 0
0 + -4x + -3x2 = 47 + -47 + -4x
-4x + -3x2 = 47 + -47 + -4x

Combine like terms: 47 + -47 = 0
-4x + -3x2 = 0 + -4x
-4x + -3x2 = -4x

Add '4x' to each side of the equation.
-4x + 4x + -3x2 = -4x + 4x

Combine like terms: -4x + 4x = 0
0 + -3x2 = -4x + 4x
-3x2 = -4x + 4x

Combine like terms: -4x + 4x = 0
-3x2 = 0

Solving
-3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-3'.
x2 = 0

Simplifying
x2 = 0

Take the square root of each side:
x = {0}

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